Your Ti-Nspire programs are my drug of choice, they are addictive, will enjoy them for rest of my life

Thank you.  I had been hesitating to make the purchase as I had wanted to get the apps for TI Voyage 200; 

but I decided to get the ones for TI-Nspire CAS CX instead, basically because it has more memory available.   

These apps you sell have the potential to become addictive so I most likely will be back for more!  

I think I made the right choice.

So, needless to say, I am very impressed.

Beauty is in the eye of the beholder.  Your programs are my drug of choice.  

I am sure to enjoy them for the remainder of my life.  

They are one of the few things worth buying besides food and a good pair of boots.

Impressed with Calculus Made Easy for Ti-Nspire

Hi Mike

I was so impressed with CME that I bought AME and PME and they are both first-rate.

I’ll be buying more as they appear.

Your apps have made the Nspire a lot more useful to me than it was – in fact, I’m beginning to like it quite a lot.

Congratulations on the hard work, I suspect your nspire apps will be even more successful than the Ti89 apps.

Best wishes

Partial Derivatives using the TiNspire Cx CAs

Finding Partial Derivatives using the TiNspire can easily be done using Calculus Made Easy at www.tinspireapps.com as follows: In the Menu select Multivariable Calculus, then select Partial Derivatives and Gradient:

Next enter the given function using x and y as variables:

The two partial derivatives are highlighted , the 2. partial derivatives are found shown below.

You do have the option to evaluate the partial derivatives by entering x0 and y0 values in the 2. box as shown below :

Logarithms using the TiNspire CX

Say we have to logarithm base 6 of the cube root of 3 , here is how we enter it into the TiNspire CX CAS:

Upon pressing ENTER we will see the pretty format and the answer:

Let’s do another example: Logarithm base 6 of 1296 :

Pressing ENTER yields the solution 4 (since 1296 = 6^4) :

Here is exponential equation involving logarithm:

This is how it is entered:

Conveniently, log base 10 and exponential base 10 function cancel to get

Now we solve this function:


Lastly, evaluate

We enter as

to get

The reason for that clean answer is using the ln rules as follows:

and lastly

We have to solve the following logarithmic equation:

Enter as

log((r+15)^2,3) = 4 and lastly

solve( log((r+15)^2,3) = 4 , r)

which solves for r using the TiNspire cx .

By hand: log_3_(r+15)^2 = 4 calls for exponentiating both sides using base 3 which yields : (r+15)^2 = 3^4 = 81
Square rooting both sides : r+15 = plus or minus 9
Thus, r = -6 or r = -24 . Plug each into the original equation to verify the correctness.

Tangent Plane – Step by Step – using the TiNspire CX

QUESTION:  Find an equation of the tangent plane to the surface
z=3x^4+9y^4+7xy at the point (3,3,1035).

SOLUTION: Start Calculus Made Easy , go to the Multivariable Calculus in the menu.

There, enter as shown below :

The steps are shown in the box below: partial derivatives are computed and evaluated. And the function is evaluated at the given point . Thus, the Tangent Plane is derived. Additionally, a line normal to the plane and a normal vector are found.

Thus, finally

Cube root, other roots and radicals using the TiNSpire CX CAS

Say you need to find 3 radical 27 , that is to find the cube root of 27. Enter it as:

and it will display as

Similarly, the 4th root of 16 is entered :

and it is displayed as

And the 5th root of x is then entered as

to be displayed as

Nice and simple. In conclusion, radicals and roots can be dealt with using the handy root-function.

Projectile Motion with the TiNspire CX – Step by Step

Here is how to perform Projectile Motion using the TiNspire CX : Launch the Physics Made Easy from www.TinspireApps.com and go to the menu option 2: Kinematics – Linear and Rotational as shown below :

Next scroll down to “Projectile At Angle”. This menu option will do step by step analysis of the projectile given initial values such as Angle, Initial Velocity and Initial height.

Here is an example:

Now, if you are to find Initial Speed, Launch Angle etc just scroll further down in the menu as we have those scenarios covered too.

Differential Gleichungen Loesen – Schrittweise – mit dem Ti-Nspire CX CAS

Nehmen wir als Bespiel die homogene Differentialgleichung 2. Ordnung :

y” + 8y’ + 16y =0

Wir starten die TiNspire APP “Differentialgleichungen Leicht Gemacht” von www.Tinspireapps.com und gehen im Menu zu Option 4: Homogene Differentialgleichung.

Und geben einfach die DGL oben ein.

Um eine partikulaere Loesung zu finden gibt man die Anfangswert Bedingungen unten ein:

So leicht ist es schrittweise Loesungen zu Differentialgleichungen zu bekommen. Man kann diese Loesung mit der von Symbol-Lab vergleichen unter : https://www.symbolab.com/solver/ordinary-differential-equation-calculator/y”%2B8y’%2B16y%3D0

Uniform and Discrete Distribution using the TiNspire CX

Given a Discrete Probability Distribution such as the one shown below make sure that the sum of the given probabilities is 100% or 1 . If you own a TiNspire CX you can enter the distribution in the top two boxes of the Statistics Made Easy App available at www.TiNspireApps.com .

Once done you get the expected value , variance : step by step.
Optional is the value of N which allows to compute P(X>N) , P(X<N) etc

For a uniform distribution , you enter the given interval [a,b] and the value c which lies on [a,b] . You will then find P(X<c) and P(X>c)

2. Fundamental Theorem of Calculus using the TiNspire – Step by Step

Applying the Fundamental Theorem of Calculus using the TiNspire – Step by Step – can easily be done using Calculus Made Easy at www.TiNspireapps.com . Here is an example:

Just enter the given function f(t) which is the integrand.

Next, enter the upper bound of the given definite integral.

Then , Calculus Made Easy provides you with the Theorem and also applies it to show the correct answer.

Steps for the computation can be seen below: First the integrand is integrated and evaluated using the given bounds . Lastly, differentiation yields that final answer.